Nameless's Topics (224)

Ngl what MC did is making me laugh and be mad at him bcs I also do the things he does....like bitch??? Be fucking selfish for once, and no. I do not mean being selfish when it comes to candies and food, I meant about yourself.

OMG YESS but we might start seeing that in season 2, here's hoping

The poison that the witch made got rid of the baby

Ohhh omg

Only if seme will do something about his seedless weapon (￣∇￣")

Omd did they say he got vasectomy ?

RIGHT I FORGOT ABOUT THAT but they can be reversible so.. if they ever do want a kid... please I hope they do

Yep in the early chapters, seme said that to uke

Yeah hopefully seme will do this

Yo chill.... I don't understand what he's saying though but i agree with you! (≡^∇^≡)

not really, to factor those kinds of equations the middle 2 numbers need to add up into a certain number and and multiply into a certain number. In this case it would be 2x and 3x in the middle. After that you can just factor normally. box method can be used but it’s not the defacto method to solving simple quadratics! :D

(add up to equal bx and multiply to equal c)

I realized that. It jumpscared at some point.

He actually explained it correctly - A in college Algrebra, the answer is (x+2)(x+3)
multiplies to give you 6 (3×2) and adds to give you 5 (3+2)

Good old time.
x² + 5x + 6 = x² + 2x + 3x + 6 = x ( x + 2) + 3(x+2) = (x+2) (x+3).

he explained it correctly though. theres a lot of ways to solve it, theres the quadratic fomula, in the example they were solving when its that easy you can even just do it mentally

A in college Algebra? Over what 11 years old can solve in middle school? Hayaa. We did not do petty factorization at university (in my field at least), the most math we did was solving matrix or computing actuarial statistics.

Box method ? Never heard it or used it to factor .we always solved it by breaking x and taking commons.well there are many ways to solve a math .I guess different countries teach the one they find easy.

I call it the box method I'm not sure what the official name is but basically it goes like this

First the basic step, finding two numbers that multiple to 6 and add to 5 which is 2 and 3

Then I make a box kind sort of like four square. The top left of the box is has X^2 and the top right has 2x, the bottom left has 3x and the bottom right has 6.

Then I try to find the factors by finding what they have in common from the collums and rows. For example the columns x^2 and 3x have X in common (technically it's 1x but in my country we write 1x and just x) then the next column 2x and 6 it's 2.

Moving onto rows x^2 and 2x have they have X in common and the next row 3x and 6 they have 2 in common.

Then I just gather my numbers making (x + 2) and (x+3), wish I could send images so you have a visial but eh

anyway my comment explained what i ment so oddly cause I was half asleep but my main point was in order to even solve/factor the equation always has to equal zero, if it doesn't you have to move some terms to make it equal 0 not 6

Thanks for the effort . This method seems like it will take time and have to do it in paper.