Since those are factors of x cubed minus y cubed, you can prove the equation by multiplying the factors back together.
distribution
bruh wtf that looks like an entire different language yeah im gonna stick to basic addition and subtracting
Do you have hmm maybe instagram or something? This would be so much easier to explain through video. I don't mind teaching through video streaming :)
no , if they r cubed then that shoud be x2+2xy+y2, also it's cubed for (x+y)^2 not for x-y
, or that at least what i remember from math
Multiply the terms x and -y by the terms x^2, xy, and y^2. Then look for the same expressions (ex; 5xy^3 and -5xy^3) and cancel it out because itself is a 0.
(X-y)(x^2+xy+y^2)=x^3-y^3
X^3+x^2y+xy^2-x^2y-xY^2-y^3=x^3-y^3
X^3-y^3=x^3-y^3
Distribution of the x first than the y to the x^2+xY+y^2
How do I verify that
(x-y)(x²+xy+y²)=x³-y³
Please I need help explaining this sum I'm gonna cry i don't understand